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Programming-Idioms

Print each key k with its value x from an associative array mymap, in ascending order of x.
Note that multiple entries may exist for the same value x.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
 for_each(begin(m), end(m),
          [&s](const auto& kv) { s.insert(kv.second); });
using System.Collections.Generic;
using System.Linq;
Dictionary<String, String> mymap = new Dictionary<String, String>();
  
foreach(KeyValuePair<string, string> a in mymap.OrderBy(x => x.Value))
{
  Console.WriteLine("Key = {0}, Value = {1}", a.Key, a.Value);
}
import std.algorithm;
import std.array;
mymap.byKeyValue
     .array
     .sort!((a, b) => a.value < b.value)
     .each!(p => writeln(p.key, " ", p.value));
mymap.entries.toList()
    ..sort((a, b) => a.value.compareTo(b.value))
    ..forEach(print);
map 
|> Map.to_list 
|> Enum.sort(fn ({_k1, val1}, {_k2, val2}) -> val1 <= val2 end)
|> Enum.each(fn ({k, v}) -> IO.puts("#{k}: #{v}") end)
import "fmt"
import "sort"
type entry struct {
	key   string
	value int
}

entries := make([]entry, 0, len(mymap))
for k, x := range mymap {
	entries = append(entries, entry{key: k, value: x})
}
sort.Slice(entries, func(i, j int) bool {
	return entries[i].value < entries[j].value
})

for _, e := range entries {
	fmt.Println("Key =", e.key, ", Value =", e.value)
}
import "fmt"
import "sort"
type entry struct {
	key   string
	value int
}

type entries []entry
func (list entries) Len() int { return len(list) }
func (list entries) Less(i, j int) bool { return list[i].value < list[j].value }
func (list entries) Swap(i, j int) { list[i], list[j] = list[j], list[i] }

entries := make(entries, 0, len(mymap))
for k, x := range mymap {
	entries = append(entries, entry{key: k, values: x})
}
sort.Sort(entries)

for _, e := range entries {
	fmt.Println("Key =", e.key, ", Value =", e.value)
}
import Data.Map as Map
import Data.List (sortBy)
import Data.Ord (comparing)
forM_ print $ sortBy (comparing snd) $ Map.toList mymap
Object.entries(mymap)
  .sort((a, b) => a[1] - b[1])
  .forEach(([key, value]) => {
    console.log('key:', key, 'value:', value);
  });
sub by_val_then_key {
    return ($mymap{$a} <=> $mymap{$b})
        or ($a cmp $b)
}

for my $k (sort by_val_then_key keys %mymap) {
   print "$k: $mymap{$k}\n";
}

for my $k (sort {($mymap{$a}<=>$mymap{$b}) or ($a cmp $b)}
           keys %mymap) {
   print "$k: $mymap{$k}\n";
}
dict_pairs(D, _, Ps),
transpose_pairs(Ps, TPs),
keysort(TPs, Val_sorted),
forall(member(V-K, Val_sorted),
       format("~w:~w~n", [V, K]))
for x, k in sorted((x, k) for k,x in mymap.items()):
    print(k, x)
import operator
for key, value in sorted(d.items(), key=operator.itemgetter(1)):
    print(key, value)
h.sort_by{|k,x| x}.each{|k,x| puts "#{k}: #{x}"}
let mut items: Vec<_> = mymap.iter().collect();
items.sort_by_key(|item| item.1);
for (k, x) in items {
    println!("[{},{}]", k, x);
}
use itertools::Itertools;
for (k, x) in mymap.iter().sorted_by_key(|x| x.1) {
	println!("[{},{}]", k, x);
}