Be concise.
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(def s2 (clojure.string/replace s1 w ""))var s2 = s1.replaceAll(w,"");s2 = String.replace(s1, w, "")S2 = string:replace(S1, W, "", all). character(len=:), allocatable :: s1
character (len=:), allocatable :: s2
character(len=:), allocatable :: w
integer :: i, j, k, tc
allocate (s2, mold=s1)
i = 1
j = 1
do
k = index (s1(i:), w)
if (k == 0) then
s2(j:j+len(s1)-i) = s1(i:)
s2 = s2(:j+len(s1)-i)
exit
else
tc = k - 1
if (tc > 0) s2(j:j+tc-1) = s1(i:i+tc-1)
i = i + tc + len(w)
j = j + tc
end if
end doBecause s2 can only be shorter than s1, it is allocated with the size of s1 and shortened to its actual length with the "s2 = s2(:j+len(s1)-i)" statement.
remove :: String -> String -> String
remove w "" = ""
remove w s@(c:cs)
| w `isPrefixOf` s = remove w (drop (length w) s)
| otherwise = c : remove w cs
s2 = remove w s1Instead of just doing the removal, define a function that does it. A function can be tested and reused.
var regex = RegExp(w, 'g');
var s2 = s1.replace(regex, '');Search pattern can also be defined in Regular Expressions. See the documentation.
If a string is used instead of regex, only the first match will be replaced.
If a string is used instead of regex, only the first match will be replaced.
const s2 = s1.split(w).join('')Better not to use a RegExp, in case the word contains dots, asterisks, &c. One may also wish to remove redundant spaces afterward: str.replace(/\s+/g, ' ')
$s2 = str_replace($w, '', $s1);s2 = s1.gsub(w, "")