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Programming-Idioms

Call th function f on every vertex accessible from the vertex v, in depth-first prefix order
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Other implementations
#include <functional>
#include <stack>
#include <unordered_set>
void dfs(Node& root, std::function<void(Node*)> f) {
  std::stack<Node*> queue;
  queue.push(&root);
  std::unordered_set<const Node*> visited;
  while (!queue.empty()) {
    Node* const node = queue.top();
    queue.pop();
    f(node);
    visited.insert(node);
    for (Node* const neighbor : node->neighbors) {
      if (visited.find(neighbor) == visited.end()) {
        queue.push(neighbor);
      }
    }
  }
}
func (v *Vertex) Dfs(f func(*Vertex), seen map[*Vertex]bool) {
	seen[v] = true
	f(v)
	for next, isEdge := range v.Neighbours {
		if isEdge && !seen[next] {
			next.Dfs(f, seen)
		}
	}
}
use Tree::Fast qw();
my $iter = $tree->traverse;
while (my $v = $iter->()) {
    f($v);
}
def depth_first(start, f):
  seen = set()
  stack = [start]
  while stack:
    vertex = stack.pop()
    f(vertex)
    seen.add(vertex)
    stack.extend(
      v for v in vertex.adjacent if v not in seen
    )
use std::rc::{Rc, Weak};
use std::cell::RefCell;
struct Vertex<V> {
	value: V,
	neighbours: Vec<Weak<RefCell<Vertex<V>>>>,
}

// ...

fn dft_helper(start: Rc<RefCell<Vertex<V>>>, f: &impl Fn(&V), s: &mut Vec<*const Vertex<V>>) {
	s.push(start.as_ptr());
	(f)(&start.borrow().value);
	for n in &start.borrow().neighbours {
		let n = n.upgrade().expect("Invalid neighbor");
		if s.iter().all(|&p| p != n.as_ptr()) {
			Self::dft_helper(n, f, s);
		}
	}
}