Creating implementation for idiom 135 : Remove item from list, by its value

Idiom

# 135 Remove item from list, by its value

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Lead paragraph

Remove at most 1 item from list _items, having value _x.
This will alter the original list or return a new list, depending on which is more idiomatic.
If there are several occurrences of _x in _items, remove only one of them. If _x is absent, keep _items unchanged.

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Other implementations

erase(items, x);

Demo

using System.Collections.Generic;

items.Remove(x);

import std.algorithm;

items = items.remove(items.countUntil!(a => a == x));

Demo
Doc

items.remove(x);

List.delete(items, x)

integer, dimension(:), allocatable :: items

i = findloc(items, x)
if (i /= 0) items = [items(1:i-1), items(i+1:)]

for i, y := range items {
	if y == x {
		copy(items[i:], items[i+1:])
		items[len(items)-1] = nil
		items = items[:len(items)-1]
		break
	}
}

Origin

for i, y := range items {
	if y == x {
		items = append(items[:i], items[i+1:]...)
		break
	}
}

Demo

import Data.List

delete x items

Java.utils.List

items.stream().findFirst().filter(item -> "x".equals(item)).ifPresent(removeIndex -> items.remove(removeIndex));

$list_position = array_search($x, $items);
$specific_item = $items[$position];
unset($specific_item);

uses classes;

i := items.IndexOf(x);
if i <> -1 then
  items.delete(i);

use List::UtilsBy qw(extract_first_by);

extract_first_by { $x eq $_ } @items;

items.remove(x)

i = items.index(x)
items.delete_at(i) unless i.nil?

if let Some(i) = items.first(&x) {
    items.remove(i);
}

Preview