Logo

Programming-Idioms

# 150 Remove trailing slash
Remove last character from string p, if this character is a slash /.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations 
 if('/' == s.back())
  s.pop_back();
p = p.TrimEnd('/');
import std.stdio : writeln;
import std.algorithm.mutation : stripRight;
auto p = "no_more_slashes///".stripRight!(a => a == '/');
writeln(p); // no_more_slashes
import std.string;
p=p.chomp("/");
if (p.endsWith("/")) p = p.substring(0, p.length - 1);
def main(string), do: String.replace_suffix(string, "/", "")
removeTrailingSlash([$/]) -> [];
removeTrailingSlash([]) -> [];
removeTrailingSlash([Ch | Rest]) ->
        [Ch] ++ removeTrailingSlash(Rest).
program x
character(len=:),allocatable :: string
integer :: ii
string='my string/'
ii=len(string)
string=trim(merge(string(:ii-1)//' ',string,string(ii:ii).eq.'/'))
write(*,*)string
end program x

import "strings"
p = strings.TrimSuffix(p, "/")
slashscrape p = if last p == '/' then init p else p
const slashscrape = p => (
  p.slice (-1) === '/' ?
    p.slice (0, -1) :
    p
)
if (p.endsWith("/")) {
    p = p.substring(0, p.length() - 1);
}
p = p.replaceAll("/$", "");
$p = rtrim($p, '/');
var
  Len: Integer;
begin
  Len := Length(p);
  if (Len > 0) and (p[Len] = '/') then Delete(P, Len, 1);
end;
uses SysUtils;
begin
  AllowDirectorySeparators := AllowDirectorySeparators + ['/'];
  p := ExcludeTrailingPathDelimiter(p);
end;
$p =~ s{/$}{};
p = p.rstrip("/")
p.chomp!("/")
p = p.chomp("/")
if p.ends_with('/') { p.pop(); }
p.stripSuffix("/")

Preview