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Programming-Idioms

# 161 Multiply all the elements of a list
Multiply all the elements of the list elements by a constant c
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Other implementations 
for E of elements loop
   E := E * c;
end loop;
for(int i = 0; i < elements_size; ++i) elements[i] *= c;
(map #(* c %1) elements)
(map #(* c %) elements)
(map (fn [e] (* c e)) elements)
(map (partial * c) elements)
for (auto &it : elements)
	it *= c;
#include <algorithm>
std::transform(std::begin(elements), std::end(elements), std::begin(elements), [c](auto i){
        return i*c;
    });
elements.Select(x => x*c)
elements[] *= c;
elements = [for (var e in elements) e * c];
elements = elements.map((e) => e * c).toList();
elements = Enum.map(elements, &(&1 * c))
elements = elements * c
for i := range elements {
	elements[i] *= c
}
map (*c) elements
elements = elements.map(x => x * c)
import static java.lang.System.out;
import java.util.List;
elements = elements.stream()
                   .map(x -> x * c)
                   .toList();
import java.util.stream.Collectors;
elements = elements.stream().map(e -> e*c).collect(Collectors.toList());
(mapcar (lambda (n) (* n c))
        elements)
local function map(t,fn)
 for i,v in ipairs(t) do
  t[i]=fn(v)
 end
 return t
end

local ret=map(elements,function(x) return x*c end)
array_map(function($v) use ($_c) {
    return $v*$c;
}, $_elements);
for i := Low(elements) to High(elements) do 
  elements[i] := elements[i] * c;
@elements = map {$_ * $c} @elements;
f = lambda x: x * c
elements = [*map(f, elements)]
elements = [c * x for x in elements]
for i, x in enumerate(elements):
    elements[i] = x * c
elements.map { |el| el * c }
elements.iter_mut().for_each(|x| *x *= c);
let elements = elements.into_iter().map(|x| c * x).collect::<Vec<_>>();
elements.map(_ * c)

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