Creating implementation for idiom 167 : Trim prefix

Idiom

# 167 Trim prefix

Created by

Lead paragraph

Create the string t consisting of the string s with its prefix p removed (if s starts with p).

New implementation

Language

Imports

Code

Documentation URL

Original attribution URL

Online runnable demo

Username

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations

#include <string.h>

size_t l = strlen(p);
const char * t = strncmp(s, p, l) ? s : s + l;

#include <string>

std::string t = s.starts_with(p) ? s.substr(p.size()) : s;

var t = s.TrimStart(p);

import std.string;

string t = s.chompPrefix(p);

var t = s.startsWith(p) ? s.substring(p.length, s.length) : s;

var t = s.startsWith(p) ? s.replaceFirst(p,"") : s;

  if (index(s,p) == 1) then
     t = s(len(p)+1:)
  else
     t = s
  end if

import "strings"

t := strings.TrimPrefix(s, p)

import qualified Data.Maybe as Maybe
import qualified Data.List as List

t = Maybe.fromMaybe s $ List.stripPrefix p s

let t = s.startsWith(p) ? s.substring(p.length) : s;

import static java.util.regex.Pattern.quote;

String t = s.replaceFirst('^' + quote(p), "");

String t = s.replaceFirst("^" + p, "");

int i = s.indexOf(p), n = p.length();
t = i == 0 ? s.substring(n) : s;

local t = (s:sub(0, #p) == p) and s:sub(#p+1) or s

$t = strpos($s, $p) === 0 ? substr($s, strlen($p)) : $s;

uses StrUtils;

if AnsiStartsStr(p, s) then 
  t := copy(s, length(p)+1, length(s)-length(p))
else
  s := t;

if (0 == index $s, $p) {
    my $t = substr $s, length $p;
}

t = s[s.startswith(p) and len(p):]

t = s.removeprefix(p)

t = s.delete_prefix(p)

t = s.sub(/\A#{p}/, "")

let t = s.strip_prefix(p).unwrap_or(s);

let t = if s.starts_with(p) { &s[p.len()..] } else { s };

let t = s.trim_start_matches(p);