Logo

Programming-Idioms

# 167 Trim prefix
Create the string t consisting of the string s with its prefix p removed (if s starts with p).
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
#include <string.h>
size_t l = strlen(p);
const char * t = strncmp(s, p, l) ? s : s + l;
var t = s.TrimStart(p);
import std.string;
string t = s.chompPrefix(p);
var t = s.startsWith(p) ? s.replaceFirst(p,"") : s;
var t = s.startsWith(p) ? s.substring(p.length, s.length) : s;
  if (index(s,p) == 1) then
     t = s(len(p)+1:)
  else
     t = s
  end if
import "strings"
t := strings.TrimPrefix(s, p)
import qualified Data.Maybe as Maybe
import qualified Data.List as List
t = Maybe.fromMaybe s $ List.stripPrefix p s
let t = s.startsWith(p) ? s.substring(p.length) : s;
String t = s.replaceFirst("^" + p, "");
local t = (s:sub(0, #p) == p) and s:sub(#p+1) or s
$t = strpos($s, $p) === 0 ? substr($s, strlen($p)) : $s;
uses StrUtils;
if AnsiStartsStr(p, s) then 
  t := copy(s, length(p)+1, length(s)-length(p))
else
  s := t;
if (0 == index $s, $p) {
    my $t = substr $s, length $p;
}
t = s[s.startswith(p) and len(p):]
t = s.removeprefix(p)
t = s.delete_prefix(p)
t = s.sub(/\A#{p}/, "")
let t = s.trim_start_matches(p);
let t = s.strip_prefix(p).unwrap_or(s);
let t = if s.starts_with(p) { &s[p.len()..] } else { s };