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Programming-Idioms

Retrieve the contents of file at path into a list of strings lines, in which each element is a line of the file.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
#include <fstream>
std::ifstream file (path);
for (std::string line; std::getline(file, line); lines.push_back(line)) {}
using System.IO;
using System.Collections.Generic;
using System.Linq;
        public List<string> GetLines(string _path)
        {
            return File.ReadAllLines(_path).ToList();
        }
import 'dart:io';
var lines = File(path).readAsLinesSync();
import "os"
import "strings"
func readLines(path string) ([]string, error) {
	b, err := os.ReadFile(path)
	if err != nil {
		return nil, err
	}
	lines := strings.Split(string(b), "\n")
	return lines, nil
}
import fs from "fs";
fs.readFileSync(path).split("\n")
import java.io.File;
import java.nio.file.Files;
import java.util.List;
List<String> lines = Files.readAllLines(new File(path).toPath());
import java.io.File;
import java.nio.file.Files;
import java.util.List;
import java.util.stream.Collectors;
String text = Files.readString(new File(path).toPath());
List<String> lines = text.lines().collect(Collectors.toList());
import java.io.File
val lines = File(path).readLines()
$lines = file($path);
if ($lines === false)
  die("Can't open file $path");
uses Classes;
var
  Lines: TStringList;
...
  Lines := TStringList.Create;
  Lines.LoadFromFile(Path);
use Path::Tiny qw(path);
my @lines = path($path)->lines;
with open(path) as f:
    lines = f.readlines()
lines = open(path).readlines
use std::io::prelude::*;
use std::io::BufReader;
use std::fs::File;
let lines = BufReader::new(File::open(path).unwrap())
	.lines()
	.collect::<Vec<_>>();
Dim lines = IO.File.ReadAllLines(path).ToList