Logo

Programming-Idioms

# 213 Case-insensitive string compare
Compare four strings in pair-wise variations. The string comparison can be implemented with an equality test or a containment test, must be case-insensitive and must apply Unicode casefolding.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations 
code (C) when $a =< C andalso C =< $z -> C - $a;
code (C) when $A =< C andalso C =< $Z -> C - $A;
code(C) -> C.

isSame([C | Rest1], [C | Rest2]) when is_integer(C)->
        isSame(Rest1, Rest2);
isSame([C1 | Rest1], [C2 | Rest2]) ->
        case (code(C1) - code(C2)) of
                0 -> isSame(Rest1, Rest2);
                _ -> false
        end;
isSame([], []) -> true;
isSame(_, _) -> false.
code (C) when $a =< C andalso C =< $z -> C - $a;
code (C) when $A =< C andalso C =< $Z -> C - $A;
code(C) -> C.

isSame([C | Rest1], [C | Rest2]) when is_integer(C)->
        isSame(Rest1, Rest2);
isSame([C1 | Rest1], [C2 | Rest2]) ->
        (code(C1) == code(C2)) andalso isSame(Rest1, Rest2);
isSame([], []) -> true;
isSame(_, _) -> false.
//no code here: see comments
use utf8;
use Test::More;
my @strings = ('ᾲ στο διάολο', 'ὰι στο διάολο', 'Ὰͅ ΣΤΟ ΔΙΆΟΛΟ', 'ᾺΙ ΣΤΟ ΔΙΆΟΛΟ');
my @indices = (
    [0,1], [0,2], [0,3],
    [1,0], [1,2], [1,3],
    [2,0], [2,1], [2,3],
    [3,0], [3,1], [3,2]
);
for my $tuple (@indices) {
    ok $strings[$tuple->[0]] =~ qr"\Q$strings[$tuple->[1]]"i;
}
done_testing;
import itertools
strings = ['ᾲ στο διάολο', 
           'ὰι στο διάολο', 
           'Ὰͅ ΣΤΟ ΔΙΆΟΛΟ', 
           'ᾺΙ ΣΤΟ ΔΙΆΟΛΟ']

for a, b in itertools.combinations(strings, 2):
    print(a, b, a.casefold() == b.casefold())

strings = ['ᾲ στο διάολο', 'ὰι στο διάολο', 'Ὰͅ ΣΤΟ ΔΙΆΟΛΟ', 'ᾺΙ ΣΤΟ ΔΙΆΟΛΟ']

strings.combination(2){|a,b| puts "#{a} equals #{b}: #{a.casecmp?(b)}" }
use itertools::Itertools;
for x in strings
    .iter()
    .combinations(2)
    .filter(|x| x[0].to_lowercase() == x[1].to_lowercase())
{
    println!("{:?} == {:?}", x[0], x[1])
}

Preview