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Programming-Idioms

Create string t from the value of string s with each sequence of spaces replaced by a single space.

Explain if only the space characters will be replaced, or the other whitespaces as well: tabs, newlines.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
using System.Text.RegularExpressions;
string t = Regex.Replace(s, @"\s+", " ");
using System.Text.RegularExpressions;
string t = Regex.Replace(s, " +", " ");
var t = s.replaceAll(RegExp(r"\s+"), " ");
singleSpace(Text) ->
        singleSpace(0, Text).

singleSpace(_, []) -> [];
singleSpace(32, [32 | Rest]) ->
        singleSpace(32, Rest);
singleSpace(32, [Ch | Rest]) ->
        [Ch] ++ singleSpace(Ch,  Rest);
singleSpace(Last, [Ch | Rest]) ->
                [Ch] ++ singleSpace(Ch, Rest).


%%singleSpace("this is  a      text  with        multiple spaces").
import "regexp"
whitespaces := regexp.MustCompile(`\s+`)
t := whitespaces.ReplaceAllString(s, " ")
def t = s.replaceAll(/\s+/, ' ')
let t = s.replace(/\s+/g, ' ');
String t = s.replaceAll("\\s+", " ");
String t = s.replaceAll(" +", " ");
local t = s:gsub("%s+", " ")
$t = $s;
do $t = str_replace('  ', ' ', $t, $count); while($count);
$t = preg_replace('/\s+/', ' ', $s);
var
  i, j: integer;
  t,s: string;
const
  whitespace = [#32,#13,#10,#9];
begin
  ....
  t := '';
  j := 0;
  setlength(t, length(s));
  for i := 1 to length(s) do
    if not ((s[i] in whitespace) and 
            ((i < length(s)) and (s[i+1] in whitespace))) then
    begin
      inc(j);
      t[j] := s[i];
    end;
  setlength(t,j);
end.
uses sysutils;
  t := s;
  while Pos('  ',t) > 0 do
    t := StringReplace(t, '  ', ' ', [rfReplaceAll]);
regexpr
  t := ReplaceRegExpr('\s+',s,' ',False);
my $t = $s;
$t =~ s/ +/ /g;
my $t = $s;
$t =~ s/\s+/ /g;
import re
t = re.sub(' +', ' ', s)
t = s.squeeze(" ")
use regex::Regex;
let re = Regex::new(r"\s+").unwrap();
let t = re.replace_all(s, " ");
Imports System.Text.RegularExpressions
Dim t As String = Regex.Replace(s, " +", " ")
Imports System.Text.RegularExpressions
Dim t As String = Regex.Replace(s, "\s+", " ")