Logo

Programming-Idioms

Create string t from string s, keeping only digit characters 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
(require '[clojure.string :as str])
(let [s "1a22b3c4de5f6"
      t (str/replace s #"[^\d]" "")]
  (println t))
using System.Linq;
var t = string.Concat(s.Where(c => char.IsDigit(c)));
var t = String.fromCharCodes(
	s.codeUnits.where((x) => (x ^ 0x30) <= 9) );
import "regexp"
re := regexp.MustCompile("[^\\d]")
t := re.ReplaceAllLiteralString(s, "")
t = filter (`elem` ['0'..'9']) s
t = s.replace(/[^\d]/gm,"");
StringBuilder tb = new StringBuilder();
for (int i=0; i<s.length(); i++){
    if(Character.isDigit(s.charAt(i)))
        tb.append(s.charAt(i));
}
String t = tb.toString();
String t = s.replaceAll("\\D+", "");
(let ((*t* (remove-if-not #'digit-char-p *s*)))
	(format t "~A~%" *t*))
for i := 1 to length(s) do
    if s[i] in ['0'..'9'] then
        t := t + s[i];
uses RegExpr;
t := ReplaceRegExpr('[^\d]', s, ''); 
my $t = $s;
$t =~ s/\D+//g;
($t = $s) =~ tr/0-9//cd;
import re
t = re.sub(r"\D", "", s)
t = s.delete("^0-9")
let t: String = s.chars().filter(|c| c.is_digit(10)).collect();