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Programming-Idioms

Print each index i and value x from the list items, from the last down to the first.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
for(int i = items.Count - 1; i >= 0; i--)
{
    Console.WriteLine($"Index = {i}, Item = {items[i]}");
}
var i = items.length ;
for (var e in items.reversed) {
  i--;
  print("$i, $e");
}
do i=size(items),1,-1
  print *,i,items(i)
end do
import "fmt"
for i := len(items) - 1; i >= 0; i-- {
	x := items[i]
	fmt.Printf("Item %d = %v \n", i, x)
}
[...items].reverse().forEach((item, index) => 
console.log(Math.abs(index -= items.length), item));
for(int i = items.length-1;i>=0;i--){
	System.out.println("Index:"+ i +", Value:" + items[i]); 
}
import static java.lang.System.out;
import static java.util.stream.IntStream.iterate;
int n = items.size();
iterate(n - 1, i -> i - 1)
    .limit(n)
    .forEach(i -> {
        out.println(i + " " + items.get(i));
    });
import static java.lang.System.out;
T x;
int i = items.size() - 1;
while (i != -1) {
    x = items.get(i);
    out.printf("%s %s%n", i--, x);
}
import static java.lang.System.out;
import static java.util.Collections.reverse;
reverse(items);
int i = items.size() - 1;
for (T x : items)
    out.printf("%s %s%n", i--, x);
for i := items.count-1 downto 0 do writeln(i,' ',items[i]);
for ($i = $#items; $i >= 0; $i--) {
    print "$i $items[$i]\n";
}
for i, x in enumerate(reversed(items)):
  print(f'{i} {x}')
for i in range(len(items)-1, -1, -1):
    print(i, items[i])
x = enumerate(items)
print(*reversed([*x]))
items.each_with_index.reverse_each{|x, i| puts "#{i} #{x}" }
for (i, item) in items.iter().enumerate().rev() {
    println!("{} = {}", i, *item);
}
  for (i, x) in items.iter().rev().enumerate() {
    println!("{i} = {x}");
  }
(define (reversed-inspect items)
  (foldl (lambda (x i)
          (display (format "~a ~a\n" i x))
          (sub1 i))
         (sub1 (length items))
        (reverse items)))