Creating implementation for idiom 342 : Leap year?

Idiom

# 342 Leap year?

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Determine if the current year is a leap year.

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final thisYear = DateTime.now().year;
final isLeap = DateTime(year, 2, 29).month == 2;

import static java.lang.Integer.parseInt;
import static java.lang.System.currentTimeMillis;

int y = parseInt("%tY".formatted(currentTimeMillis()));
boolean b = y % 4 == 0 && (y % 100 != 0 || y % 400 == 0);

import java.time.Year;

boolean b = Year.now().isLeap();

SysUtils

if IsLeapYear(SomeYear) then writeln('SomeYear is a leap year')

import calendar
import datetime

if calendar.isleap(datetime.date.today().year):
    print('This year is a leap year.')

not y % 4 and (y % 100 != 0 or not y % 400)

from datetime import date
from calendar import isleap

year = date.today().year
is_leap_year = isleap(year)

leap_year = False
if not year % 4:
    if year % 100 or not year % 400:
        leap_year = True

require 'date'

Date.leap?( Date.today.year )

let leap_year = year % 4 == 0 && (year % 100 != 0 || year % 400 == 0);