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Programming-Idioms

# 356 Parse list of integers
Create the list of integers items for the string s containing integers separated by one or more whitespace characters (space, tab, newline).
New implementation

Be concise.

Be useful.

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Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations 
import "fmt"
import "strconv"
parts := strings.Fields(s)
items := make([]int, len(parts))
for i, part := range parts {
	v, err := strconv.Atoi(part)
	if err != nil {
		return err
	}
	items[i] = v
}
import java.util.List;
import java.util.Scanner;
Scanner t = new Scanner(s);
List<Integer> items = t.tokens()
    .map(Integer::parseInt)
    .toList();
t.close();
import java.util.Scanner;
Scanner t = new Scanner(s);
int items[] = t.tokens()
    .mapToInt(Integer::parseInt)
    .toArray();
t.close();
import java.util.Scanner;
Scanner t = new Scanner(s);
Integer items[] = t.tokens()
    .map(Integer::valueOf)
    .toArray(Integer[]::new);
t.close();
import static java.util.stream.Collectors.toCollection;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
Scanner t = new Scanner(s);
List<Integer> items = t.tokens()
    .map(Integer::parseInt)
    .collect(toCollection(ArrayList::new));
t.close();
var
  tmp: array of string;
  items: array of integer;
...  
tmp := s.split(whitespace, TStringsplitOptions.ExcludeEmpty);
SetLength(items, Length(tmp));
for i := Low(tmp) to High(tmp) do items[i] := StrToInt(tmp[i]);
items = [*map(int, s.split())]
items = [int(x) for x in s.split()]
items = s.split.map(&:to_i)

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