Implement a function compose which returns composition function g ∘ f for any functions f and g having exactly 1 parameter.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
(comp g f)
template<typename Pred1, typename Pred2>
auto compose(Pred1 f, Pred2 g){
  return [f,g](auto x){ return g(f(x)); };	
using System;
Func<T1, T3> compose<T1, T2, T3>(Func<T1, T2> f, Func<T2, T3> g) => x => g(f(x));
auto _compose(T)(T function(T) f, T function(T) g)
    auto lambda = (T x) { return g(f(x));  };
    return lambda;
compose(f, g) => (x) => g(f(x));
-spec compose(fun((X) -> Y), fun((Y) -> Z)) -> fun((X) -> Z).
compose(F, G) -> fun(X) -> G(F(X)) end.
func composeIntFuncs(f func(int) int, g func(int) int) func(int) int {
	return func(x int) int {
		return g(f(x))
compose f g = g . f
const compose = f => g => x => g(f(x));
function compose(f,g){
    return function(x){
        return g(f(x));
    default <V> Function<V, R> compose(Function<? super V, ? extends T> before) {
        return (V v) -> apply(before.apply(v));
(defun compose (f g)
  (lambda (x) (g (f x))))
function compose(f,g)
   return function(x)
      return g(f(x))
function compose($f,$g){
	return function($x) use($f,$g) {
		return $g($f($x));
sub compose {
   my ($f, $g) = @_;
   return sub {
      my $x = shift;
      return $g->($f->($x));
def compose(f, g):
	return lambda x: g(f(x))
def compose(f, g)
  -> x { g.(f.(x)) }
def compose(f, g)
  f >> g
fn compose<A, B, C>(f: impl Fn(A) -> B, g: impl Fn(B) -> C) -> impl Fn(A) -> C {
    move |x| g(f(x))
fn compose<'a, A, B, C, G, F>(f: F, g: G) -> Box<Fn(A) -> C + 'a>
	where F: 'a + Fn(A) -> B, G: 'a + Fn(B) -> C
	Box::new(move |x| g(f(x)))
(define (compose f g) 
	(lambda x 
		(f (apply g x))))
(define compose
 (lambda (f g)
   (lambda (x) (f (g x)))))
Imports System
Function Compose(Of T1, T2, T3)(f As Func(Of T1, T2), g As Func(Of T2, T3)) As Func(Of T1, T3)
    Return Function(x) g(f(x))
End Function