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Programming-Idioms

# 364 Calculate the magnitude symbol for a value
Calculate the SI (International System of Units) prefix, x, of value a.

For example, 'k', 'M', 'G', 'T', etc.

https://en.wikipedia.org/wiki/Metric_prefix
New implementation

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Other implementations 
#include <cmath>
#include <vector>
using namespace std;
struct units {
    double y;
    vector<char> a;
    units(int x) { y = log(x); }
    void add(char x) { a.push_back(x); }
    pair<int, char> get(int x) {
        int i (log(x) / y);
        return {i, a[i - 1]};
    }
};
units u {1'000};
for (char x : "kMGT") u.add(x);
pair p {u.get(a)};
a /= pow(1'000, p.first);
char x {p.second};
#include <cmath>
int y (log(a) / log(1'000));
a /= pow(1'000, y);
char x {"kMGT"[y - 1]};
import static java.lang.Math.log;
import static java.lang.Math.pow;
enum SI {
    k("kilo"),
    M("mega"),
    G("giga"),
    T("tera");
    String s;
    static double y = log(1_000);
    SI(String s) { this.s = s; }
    static SI get(double x) {
        int y = (int) (log(x) / SI.y);
        return values()[y - 1];
    }
}
SI si = SI.get(a);
a /= pow(1_000, si.ordinal() + 1);
String x = si.name();
import static java.lang.Math.log;
import static java.lang.Math.pow;
int y = (int) (log(a) / log(1_000));
a /= pow(1_000, y);
char x = "kMGT".charAt(y - 1);
function GetSIPrefix(AValue: Double): string;
const
  SIPrefixes: array[1..24] of String = ('Q','R','Y', 'Z','E','P','T','G','M','K','H','D','','d','c','m','µ','mc','n','p','f','a','z','y');
  SIFactors:  array[1..24] of Double = (1E+30,1E+27,1E+24, 1E+21, 1E+18, 1E+15, 1E+12, 1E+9, 1E+6, 1E+3,1E+2,1E+1,1,1E-1,1E-2,
var
  i: Integer;
begin
  Result := '';
  for i := 1 to 24 do
  begin
    if (Abs(AValue) >= SIFactors[i]) then
    begin
      Exit(SIPrefixes[i]);
    end;
  end;
end;
from enum import StrEnum
from math import log
class Units(StrEnum):
    k = 'kilo'
    M = 'mega'
    G = 'giga'
    T = 'tera'
    @classmethod
    def parse(cls, x):
        y = log(x) / log(1_000)
        u = [*cls][int(y) - 1]
        u.y = y
        return u
u = Units.parse(a)
a /= 1_000 ** int(u.y)
x = u.name
from math import log
y = int(log(a, 1_000))
a /= 1_000 ** y
x = 'kMGT'[y - 1]
m = {f'{a / 1e12} T': a > 999_999_999_999,
     f'{a /  1e9} G': a > 999_999_999,
     f'{a /  1e6} M': a > 999_999,
     f'{a /  1e3} k': a > 999,
     f'{a} ': ...}
s = next(k for k, v in m.items() if v)
x =  case a
  when 1e3... 1e6 ; "k"
  when 1e6... 1e9 ; "M"
  when 1e9... 1e12; "G"
  when 1e12...1e15; "T"
  else ""
end

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