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Programming-Idioms

Find substring t consisting in characters i (included) to j (excluded) of string s.
Character indices start at 0 unless specified otherwise.
Make sure that multibyte characters are properly handled.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
T : String := S (I .. J - 1);
#include <stdlib.h>
#include <string.h>
char *t=malloc((j-i+1)*sizeof(char));
strncpy(t,s+i,j-i);
(def t (subs s i j))
#include <string>
auto t = s.substr(i, j-i);
var t = s.Substring(i, j - i);
auto t = s[i .. j];
var t = s.substring(i, j);
t = String.slice(s, i..j-1)
T = string:sub_string(I, J-1).
character(len=:), allocatable :: t

  t = s(i:j-1)
t := string([]rune(s)[i:j])
def t = s[i..<j]
t = drop i (take j s)
let t = s.substring(i, j);
let t = s.slice(i, j);
String t = s.substring(i,j);
val t = s.substring(i, j)
(setf u (subseq s i j))
local t = s:sub(i, j - 1)
@import Foundation;
t=[s substringWithRange:NSMakeRange(i,j-i)]
$t = mb_substr($s, $i, $j-$i, 'UTF-8');
t := copy(s,i+1,j-i);
uses Sysutils;
t := s.Substring(i,j-i);
my $chunk = substr("now is the time", $i, $j);
t = s[i:j]
t = s[i..j-1] 
use substring::Substring;
let t = s.substring(i, j);
extern crate unicode_segmentation;
use unicode_segmentation::UnicodeSegmentation;
let t = s.graphemes(true).skip(i).take(j - i).collect::<String>();
val t = s.substring(i, j)
(define t (substring s i j))
t := s copyFrom: i to: j - 1.
Dim t As String = s.Substring(i,j)