Creating implementation for idiom 97 : Check string suffix

Idiom

# 97 Check string suffix

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Lead paragraph

Set boolean b to true if string s ends with string suffix, false otherwise.

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Other implementations

(require '[clojure.string :as str])

(let [b (str/ends-with? s suffix)]
   ; ...  
 )

return suffix.size() == s.size() - s.rfind(suffix);

Demo

#include <string>

bool b = s.ends_with(suffix);

var _b = _s.EndsWith(_suffix);

bool b = s.EndsWith(suffix);

import std.algorithm.searching;

b = s.endsWith(suffix);

var b = s.endsWith(suffix);

Demo

b = String.ends_with?(s, suffix)

  b = (s(len(s)-len(suffix)+1:) == suffix)

import "strings"

b := strings.HasSuffix(s, suffix)

Demo
Doc

final b = s.endsWith(suffix)

Demo
Doc

import Data.Text

b = isSuffixOf suffix s

var b = s.endsWith(suffix);

boolean b = s.endsWith(suffix);

b = s.endsWith(suffix)

Demo
Doc


(defun check-suffix (str suf )
  (if (> (length suf) (length str )) nil (equalp (subseq str (- (length str) (length suf)) (length str )) suf )))

(setf b (check-suffix s suffix))

b = s:sub(-string.len(suffix)) == suffix

$b = (bool)preg_match("/{$suffix}$/", $s);

uses strutils;

b := AnsiEndsStr(suffix, s);

$b = $suffix eq substr($s, -length($suffix));

b = s.endswith(suffix)

b = s.end_with?(suffix)

Demo
Doc

let b = s.ends_with(suffix);

val b = s.endsWith(suffix)

Preview