Editing Idiom 165 : Last element of list

Idiom

# 165 Last element of list

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Lead paragraph

Assign to variable _x the last element of list _items.

Implementation

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Imports

Code

int[] items;
auto x = items.back();

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Online demo

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Other implementations

x := items[len(items)-1]

const x = items[items.length - 1];

x = items.last

x = items.last

x = items[-1]

x := items[high(items)];

val x = items.takeRight(1)

foo :: [a] -> Maybe a
foo [] = Nothing
foo xs = Just $ last xs

x = foo items

int[42] items;
int x = items[$-1];

x = items.last;

local x = items[#items]

let x = items[items.len()-1];

my $x = $items[-1];

$x = end($items);

let x = items.last().unwrap();

using System.Linq;

var x = items.LastOrDefault();

x = List.last(items)

int x = items[items.length - 1];

x = lists:last(items),

x = last items

(last items)

#include<vector>

std::vector<int> items;
int last = items.back();

x = items(ubound(items,1))

var x = items.last()

$x = $items[array_key_last($items)];

#include <iterator>

auto x = *std::crbegin(items);

my $x = $items[$#items];

Dim ItemList As New List(Of String)(New String() {"one", "two", "three"})
Console.WriteLine(ItemList.Last)