Editing Idiom 38 : Extract a substring

Idiom

# 38 Extract a substring

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Lead paragraph

Find substring _t consisting in characters _i (included) to _j (excluded) of string _s.
Character indices start at _0 unless specified otherwise.
Make sure that multibyte characters are properly handled.

Implementation

Language

PHP

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Imports

Code

$t = mb_substr($s, $i, $j-$i, 'UTF-8');

Documentation URL

Original attribution URL

Online demo

Edit summary

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Implementation edit is for fixing errors and enhancing with metadata.

Instead of changing the code of the snippet, consider creating another PHP implementation.

Other implementations

String t = s.substring(i,j);

Demo

t = s[i..j-1]

Demo
Doc

t = s[i:j]

Origin

var t = s.substring(i, j);

my $chunk = substr("now is the time", $i, $j);

let t = s.substring(i, j);

#include <stdlib.h>
#include <string.h>

char *t=malloc((j-i+1)*sizeof(char));
strncpy(t,s+i,j-i);

auto t = s[i .. j];

t := copy(s,i+1,j-i);

extern crate unicode_segmentation;
use unicode_segmentation::UnicodeSegmentation;

let t = s.graphemes(true).skip(i).take(j - i).collect::<String>();

Demo
Doc

t = drop i (take j s)

t = String.slice(s, i..j-1)

T = string:sub_string(I, J-1).

t := string([]rune(s)[i:j])

Demo

t = s:sub(i, j-1)

#include <string>

auto t = s.substr(i, j-i);

Demo
Doc

var t = s.Substring(i, j - i);

T : String := S (I .. J - 1);

uses Sysutils;

t := s.Substring(i,j-i);

(setf u (subseq s i j))

character(len=:), allocatable :: t

  t = s(i:j-1)

(def t (subs s i j))

Dim t As String = s.Substring(i,j)

let t = s.slice(i, j);

def t = s[i..<j]

Demo
Doc

@import Foundation;

t=[s substringWithRange:NSMakeRange(i,j-i)]

use substring::Substring;

let t = s.substring(i, j);

Preview