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Programming-Idioms

  • Python
  • Rust

Idiom #330 Map to list

Create the list a containing all the values of the map m.

Ignore the keys of m. The order of a doesn't matter. a may contain duplicate values.

a = list(m.values())
a = [*m.values()]
use std::collections::HashMap;
let a = m.into_values().collect::<Vec<_>>();

m is no longer useable as into_values() takes ownership of m. Use values() to borrow the values.
using System.Linq;
var a = m.Values.ToList();
New implementation...
< > ⌨
programming-idioms.org 
a = list(m.values())
a = [*m.values()]
let a = m.into_values().collect::<Vec<_>>();
var a = m.Values.ToList();
a = Map.values(m)
a := make([]V, 0, len(m))
for _, v := range m {
	a = append(a, v)
}
a := maps.Values(m)
Type
  TMap = specialize TFPGMap<TKey, TData>;
  TList = specialize TFPGList<TData>;
var
  m: TMap;
  a: TList;

...
  a := TList.Create;
  for idx := 0 to m.count-1 do
    aList.Add(m.Data[idx]);

@a = values %m;
a = m.values