Idiom #117 Get list size

Set n to the number of elements of the list x.

val n = x.size

with Ada.Containers.Vectors;
use Ada.Containers;

N : Count_Type := X.Length;

int n;
int x[5];
n = sizeof(x)/sizeof(*x);

size_t n = sizeof(x)/sizeof(*x);

(def n (count x))

size_t n = x.size();

using System.Collections.Generic;

int n = x.Count;

int n = x.Length;

import std.range.primitives;

n = walkLength(x);

auto n = x.length;

int n = x.length;

n = Enum.count(x)

N = length(X).

n = size(x)

n := len(x)

def n = x.size()

let n = length x

var n = x.length;

int n = x.size();

int n = x.length;

(setf n (length x))

local n = #x

@import Foundation;

NSUInteger n=x.count;

$n = count($x);

n := length(x);

my $N = @x;

$n = scalar @x;

length(x, N).

n = len(x)

n = x.length

let n = x.len();

val n = x.size

(define n (length x))

n := x size.

Dim n As Integer = x.Count

n = UBound(x) + 1

Do you know the best way to do this in your language ? New implementation...

< > ⌨

Idiom created by programming-idioms.org

History

Related idioms

Issues