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Programming-Idioms

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  • Clojure

Idiom #163 Print list elements by group of 2

Print all the list elements, two by two, assuming list length is even.

(doseq [xs (partition 2 list)]
  (apply println xs))
#include <stdio.h>
for (unsigned i = 0; i < sizeof(list) / sizeof(list[0]); i += 2)
	printf("%d, %d\n", list[i], list[i + 1]);

I'm treating list as an array not a list because C doesn't have lists built in.
The length had better be even or there'll be undefined behaviour to pay!

New implementation...