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Programming-Idioms

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  • Python

Idiom #173 Format a number with grouped thousands

Number will be formatted with a comma separator between every group of thousands.

f'{1000:,}'
format(1000, ',')
'{:,}'.format(1000)
#define _POSIX_C_SOURCE 200809L
#include <locale.h>
#include <stdio.h>
setlocale(LC_ALL, "");
printf("%'d\n", 1000);
New implementation...
< > ⌨
cup 
f'{1000:,}'
format(1000, ',')
'{:,}'.format(1000)
setlocale(LC_ALL, "");
printf("%'d\n", 1000);
$"{1000:n}"
string f = "%3,d".format(123456);
p := message.NewPrinter(language.English)
s := p.Sprintf("%d\n", 1000)
s :: Int -> String
s = intersperseN ',' 3 . show

intersperseN :: a -> Int -> [a] -> [a]
intersperseN x n = uncurry (<>) . foldr alg ([], [])
  where
    alg a (buf', acc)
      | length buf >= n = ([], (x:buf) <> acc)
      | otherwise = (buf, acc)
      where buf = a:buf'
new Intl.NumberFormat().format(1000);
DecimalFormat f = (DecimalFormat) getNumberInstance();
f.setGroupingSize(3);
String s = f.format(1_000);
NumberFormat f = new DecimalFormat("#,###");
String s = f.format(1_234);
out.printf("%,f", 1_234.5);
out.printf("%,f", new BigDecimal("1234.5"));
out.printf("%,d", new BigInteger("1234"));
String.format("%,d", 1000000);
echo number_format(1000);
writeln(format('%.0n',[double(10000)]));   
 sub commify {
    local $_  = shift;
    1 while s/^([-+]?\d+)(\d{3})/$1,$2/;
    return $_;
}
'1000'.gsub(/\B(?=(...)*\b)/, ',')
1000.to_s(:delimited)
'1000'.reverse.scan(/.{1,3}/).join(',').reverse
println!("{}", 1000.separated_string());
"%,d".format(n)