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Idiom #191 Check if any value in a list is larger than a limit

Given a one-dimensional array a, check if any value is larger than x, and execute the procedure f if that is the case

for(int i = 0; i<a.length;i++) {
	if(a[i]>x) {
		f();
		break;
	}
}
import static java.util.stream.IntStream.of;
if (of(a).anyMatch(i -> i > x)) f();
for (int i : a)
    if (i > x) {
        f();
        break;
    }
unsigned i;
for (i = 0; i < sizeof(a) / sizeof(a[0]); ++i) {
	if (a[i] > x) {
		f();
		break;
	}
}

(when (seq (filter #(> % x) a)) (f))
#include <algorithm>
if (std::any_of(a.begin(), a.end(), [x](auto y) { return y > x; }))
    f();
using System.Linq;
if (a.Any(e => e > x))
    f();
if (a.any((value) => value > x)) f();
if (any(a > x)) call f
import "slices"
if slices.ContainsFunc(a, func(i int) bool {
	return i > x
}) {
	f()
}
for _, v := range a {
	if v > x {
		f()
		break
	}
}
if (a.any { it > x })
    f()
when (foldl1 (||) $ map (a > x)) f
if(a.some(item => item > x)){
	f()
}
if (count(array_filter($a, function($v) { return $v > $x; })))
  f();

// or with intermediate steps
$tmp = array_filter(
  $a,
  function ($v) { return $v > $x; }
)
if (count($tmp))
  f();

// or with array reduce instead
if (
  array_reduce($a, 
    function($old, $item) { return $old or ($item > $x); }
  )
)
  f();

// Array reduce takes the old result $old, and 
// applies $item (from $a) to the old result 
// iteratively. We use the 'or' boolean operator
// to implement an 'any' operation.

for v in a do if v > x then f;
use List::Util qw(any);
f if any { $_ > $x } @a;
if any(v > x for v in a):
    f()
f if a.any?{|v| v > x }
if a.iter().any(|&elem| elem > x) {
    f()
}
(let iter ((l a))
  (cond ((null? l) '())
        ((> (car l) x) (f))
        (else (iter (cdr l)))))
New implementation...
< > ⌨
tkoenig 
for(int i = 0; i<a.length;i++) {
	if(a[i]>x) {
		f();
		break;
	}
}
if (of(a).anyMatch(i -> i > x)) f();
for (int i : a)
    if (i > x) {
        f();
        break;
    }
unsigned i;
for (i = 0; i < sizeof(a) / sizeof(a[0]); ++i) {
	if (a[i] > x) {
		f();
		break;
	}
}

(when (seq (filter #(> % x) a)) (f))
if (std::any_of(a.begin(), a.end(), [x](auto y) { return y > x; }))
    f();
if (a.Any(e => e > x))
    f();
if (a.any((value) => value > x)) f();
if (any(a > x)) call f
if slices.ContainsFunc(a, func(i int) bool {
	return i > x
}) {
	f()
}
for _, v := range a {
	if v > x {
		f()
		break
	}
}
if (a.any { it > x })
    f()
when (foldl1 (||) $ map (a > x)) f
if(a.some(item => item > x)){
	f()
}
if (count(array_filter($a, function($v) { return $v > $x; })))
  f();

// or with intermediate steps
$tmp = array_filter(
  $a,
  function ($v) { return $v > $x; }
)
if (count($tmp))
  f();

// or with array reduce instead
if (
  array_reduce($a, 
    function($old, $item) { return $old or ($item > $x); }
  )
)
  f();

// Array reduce takes the old result $old, and 
// applies $item (from $a) to the old result 
// iteratively. We use the 'or' boolean operator
// to implement an 'any' operation.

for v in a do if v > x then f;
f if any { $_ > $x } @a;
if any(v > x for v in a):
    f()
f if a.any?{|v| v > x }
if a.iter().any(|&elem| elem > x) {
    f()
}
(let iter ((l a))
  (cond ((null? l) '())
        ((> (car l) x) (f))
        (else (iter (cdr l)))))