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Programming-Idioms

  • Fortran
  • Go
  • Perl

Idiom #237 Xor integers

Assign to c the result of (a xor b)

c := a ^ b

a, b, c have the same integer type (signed or unsigned)
import "math/big"
c := new(big.Int)
c.Xor(a, b)

a, b, c have big integer type *big.Int
c = ieor(a,b)
my $c = $a ^ $b;
int c = a ^ b;
New implementation...
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programming-idioms.org 
c := a ^ b
c := new(big.Int)
c.Xor(a, b)
c = ieor(a,b)
my $c = $a ^ $b;
int c = a ^ b;
(def c (bit-xor a b))
int c = a ^ b;
int c = a ^ b;
var c = a ^ b;
c = a ^^^ b
C = A bxor B
c = xor a b
const c = a ^ b;
int c = a ^ b;
c := a xor b;
c = a ^ b
c = a ^ b
let c = a ^ b;
Dim c As Integer = a Xor b