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Programming-Idioms

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  • Go

Idiom #243 Print list

Print the contents of the list or array a on the standard output.

import "fmt"
fmt.Println(a)

a is a slice.
This works fine for simple types and structs.
It won't dereference pointers.
(print a)
New implementation...
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fmt.Println(a)
(print a)
std::copy(a.begin(), a.end(), std::ostream_iterator<int>(std::cout, "\n"));
Console.WriteLine( string.Join(", ", a) );
a.ForEach(Console.WriteLine);
print(a);
Enum.each(a, &IO.inspect/1)
write (*,*) a
print a
console.table(a);
console.log(a);
out.println(deepToString(a));
System.out.println(Arrays.toString(a));
System.out.println(a);
(defun plist (lst)
  (if (< (length lst) 20 )  
      (loop for elem in lst do (p elem))
      (let ((l (length lst )))
         (p (nth 0 lst )(nth 1 lst )(nth 2 lst )(nth 3 lst )
         "... (" l " in total)... "
         (nth (- l 4) lst )(nth (- l 3 ) lst )(nth (- l 2 ) lst )(nth (- l 1 ) lst ) )
      )))

(defun p (x &rest others)
  (cond ((listp x)( plist x   ))
        ((stringp x)(format t x  ))
        (T (write x)))
  (format t " ") 
  (if others (p others))
(print a )
print(table.concat(a,", "))
print_r($a)
for el in a do writeln(el);
print "@items\n";
print join(', ', @items) . "\n";
print(a)
puts a * ", "
puts a.join(", ")
puts a
println!("{:?}", a)
(write a)