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  • Haskell

Idiom #252 Conditional assignment

Assign to the variable x the string value "a" if calling the function condition returns true, or the value "b" otherwise.

x = if condition then 'a' else 'b'
let x | condition = "a"
      | otherwise = "b"

Assignment guards
x := (if condition() then "a" else "b");
New implementation...
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programming-idioms.org 
x = if condition then 'a' else 'b'
let x | condition = "a"
      | otherwise = "b"
x := (if condition() then "a" else "b");

x := (if condition() then "a" else "b");
if condition() then
   x := "a";
else
   x := "b";
end if;
x = condition() ? "a" : "b";
(def x (if condition
         "a"
         "b"))
x = condition() ? "a" : "b";
x = condition() ? "a" : "b";
x = condition()? "a": "b";
var x = condition() ? "a" : "b";
x = if condition(), do: "a", else: "b"
X = case Condition() of
	true -> "a";
	false -> "b"
end
if (condition())
  x = a
else
  x = b
end if
if condition() {
	x = "a"
} else {
	x = "b"
}
const x = condition() ? 'a' : 'b';
x = condition() ? "a" : "b";
val x = if(condition()) "a" else "b"
(setf x (if (condition) "a" "b"))
$x = condition() ? "a" : "b";
if condition then
  x := a
else
  x := b;
x := ifthen(condition, a, b);
my $x = condition() ? "a" : "b";
x = "a" if condition() else "b"
x = ('b', 'a')[condition()]
x = 'ba'[condition()]
x = condition ? "a" : "b"

x = if condition
      "a"
    else
      "b"
    end
x = if condition() { "a" } else { "b" };
x = if condition() then "a" else "b"
x = if (condition()) "a" else "b"