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Programming-Idioms

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Idiom #340 Last character of string

Assign to c the value of the last character of the string s.

Explain the type of c, and what happens if s is empty.

Make sure to properly handle multi-bytes characters.

char c = s[^1];
final c = s[s.length - 1];
r := []rune(s)
c := r[len(r)-1]
import "unicode/utf8"
c, _ := utf8.DecodeLastRuneInString(s)
lastChar :: String -> Char
lastChar s
    | s=="" = ""
    | otherwise = s !! (length s - 1)
import static java.lang.Character.isSurrogate;
int n = s.length(), i = n - 1;
if (isSurrogate(s.charAt(i))) --i;
String c = s.substring(i);
LazUtf8
function GetLastUtfCodePoint(const S: String): String;
var
  p: PChar;
  PLen: PtrInt;
begin
  Result := '';
  p := UTF8CodepointStart(PChar(S), Length(S), Utf8Length(S) - 1);
  PLen := UTF8CodepointSize(p);
  Result := p;
  SetLength(Result,PLen);
end; 

var
  s: string;
begin
  c := GetLastUtfCodePoint(s);
end.
{$modeswitch unicodestrings}
c := s[Length(s)];
$c = substr($s, -1, 1);
c = s[-1]
c = s[-1]
let c = s.chars().last().unwrap();
New implementation...
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programming-idioms.org 
char c = s[^1];
final c = s[s.length - 1];
r := []rune(s)
c := r[len(r)-1]
c, _ := utf8.DecodeLastRuneInString(s)
lastChar :: String -> Char
lastChar s
    | s=="" = ""
    | otherwise = s !! (length s - 1)
int n = s.length(), i = n - 1;
if (isSurrogate(s.charAt(i))) --i;
String c = s.substring(i);
function GetLastUtfCodePoint(const S: String): String;
var
  p: PChar;
  PLen: PtrInt;
begin
  Result := '';
  p := UTF8CodepointStart(PChar(S), Length(S), Utf8Length(S) - 1);
  PLen := UTF8CodepointSize(p);
  Result := p;
  SetLength(Result,PLen);
end; 

var
  s: string;
begin
  c := GetLastUtfCodePoint(s);
end.
c := s[Length(s)];
$c = substr($s, -1, 1);
c = s[-1]
c = s[-1]
let c = s.chars().last().unwrap();