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Programming-Idioms

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Idiom #349 Convert a fraction into a decimal value

Parse a value, f, into a decimal number, a.

For example, `1/2` is 0.5, and `3 1/8` is 3.125.

https://en.wikipedia.org/wiki/Fraction

Fractions
a := f.ToFloat;
let z = 0, n, d, i, a
if ((i = f.indexOf(' ')) != -1) {
    z = parseInt(f.substring(0, i))
    f = f.substring(++i).trim()
}
i = f.indexOf('/')
n = parseInt(f.substring(0, i))
d = parseInt(f.substring(++i))
a = z + (n / d)
import static java.lang.Integer.parseInt;
int z = 0, n, d, i;
double a;
if ((i = f.indexOf(' ')) != -1) {
    z = parseInt(f.substring(0, i));
    f = f.substring(++i).trim();
}
i = f.indexOf('/');
n = parseInt(f.substring(0, i));
d = parseInt(f.substring(++i));
a = z + ((double) n / d);
z = 0
if (i := f.find(' ')) != -1:
    z = int(f[:i])
    f = f[i + 1:].lstrip()
n, d = map(int, f.split('/'))
a = z + (n / d)
a = f.split.map(&:to_r).sum.to_f
New implementation...
< > ⌨
reilas 
a := f.ToFloat;
let z = 0, n, d, i, a
if ((i = f.indexOf(' ')) != -1) {
    z = parseInt(f.substring(0, i))
    f = f.substring(++i).trim()
}
i = f.indexOf('/')
n = parseInt(f.substring(0, i))
d = parseInt(f.substring(++i))
a = z + (n / d)
int z = 0, n, d, i;
double a;
if ((i = f.indexOf(' ')) != -1) {
    z = parseInt(f.substring(0, i));
    f = f.substring(++i).trim();
}
i = f.indexOf('/');
n = parseInt(f.substring(0, i));
d = parseInt(f.substring(++i));
a = z + ((double) n / d);
z = 0
if (i := f.find(' ')) != -1:
    z = int(f[:i])
    f = f[i + 1:].lstrip()
n, d = map(int, f.split('/'))
a = z + (n / d)
a = f.split.map(&:to_r).sum.to_f