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Programming-Idioms

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  • Ruby

Idiom #352 Parallelize 3 computations

Execute the functions f1, f2, f3 concurrently, and assign their respective return values to a1, a2, a3.

def f1 = __method__
def f2 = __method__
def f3 = __method__

ractors = [Ractor.new{f1}, Ractor.new{f2}, Ractor.new{f3} ]
a1, a2, a3 = ractors.map(&:take)
import "sync"
var wg sync.WaitGroup
wg.Add(3)
go func() {
	a1 = f1()
	wg.Done()
}()
go func() {
	a2 = f2()
	wg.Done()
}()
go func() {
	a3 = f3()
	wg.Done()
}()
wg.Wait()

3 new goroutines

New implementation...