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Programming-Idioms

New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating resource.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
items.remove(x);
using System.Collections.Generic;
items.RemoveAll(r => r == x);
import std.algorithm.iteration;
import std.array;
items = items.filter!(a => a != x).array;
items.removeWhere((y)=>y==x);
items = pack (items,items != x)
j := 0
for i, v := range items {
	if v != x {
		items[j] = items[i]
		j++
	}
}
items = items[:j]
items2 := make([]T, 0, len(items))
for _, v := range items {
	if v != x {
		items2 = append(items2, v)
	}
}
j := 0
for i, v := range items {
	if v != x {
		items[j] = items[i]
		j++
	}
}
for k := j; k < len(items); k++ {
	items[k] = nil
}
items = items[:j]
filter (/= x) items
const newlist = items.filter(y => x !== y)
import java.util.Collections;
items.removeAll(Collections.singleton(x));
$newItems = array_diff($items, [$x]);
var
  i: integer;

for i:= items.count-1 downto 0 do
  if items[i] = x then
    items.delete(i);
my @filtered = grep { $x ne $_ } @items;
newlist = [item for item in items if item != x]
items.delete(x)
items = items.into_iter().filter(|&item| item != x).collect();
items.filter(_ != x)