Remove all occurrences of value x from list items.This will alter the original list or return a new list, depending on which is more idiomatic.
items.remove(x);
using System.Collections.Generic;
items.RemoveAll(r => r == x);
import std.algorithm.iteration; import std.array;
items = items.filter!(a => a != x).array;
items.removeWhere((y)=>y==x);
list_items = pack (list_items,list_items != x)
j := 0 for i, v := range items { if v != x { items[j] = items[i] j++ } } items = items[:j]
items2 := make([]T, 0, len(items)) for _, v := range items { if v != x { items2 = append(items2, v) } }
j := 0 for i, v := range items { if v != x { items[j] = items[i] j++ } } for k := j; k < len(items); k++ { items[k] = nil } items = items[:j]
filter (/= x) items
const newlist = items.filter(y => x !== y)
import java.util.Collections;
items.removeAll(Collections.singleton(x));
$newItems = array_diff($items, [$x]);
var i: integer; for i:= items.count-1 downto 0 do if items[i] = x then items.delete(i);
my @filtered = grep { $x ne $_ } @items;
newlist = [item for item in items if item != x]
items.delete(x)
items = items.into_iter().filter(|&item| item != x).collect();
items.filter(_ != x)
No security, no password. Other people might choose the same nickname.