Creating implementation for idiom 142 : Hexadecimal digits of an integer

Idiom

# 142 Hexadecimal digits of an integer

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Assign to string s the hexadecimal representation (base 16) of integer x.

E.g. 999 -> "3e7"

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Other implementations

char s[32];
snprintf(s, sizeof(s), "%x", i);

#include <sstream>

std::ostringstream stream;
stream << std::hex << x;
s = stream.str();

Demo

template <typename I>
std::string n2hexstr(I w, size_t hex_len = sizeof(I)<<1) {
    static const char* digits = "0123456789ABCDEF";
	std::string str(hex_len, '-');
    for (size_t i=0, j=(hex_len-1)*4 ; i<hex_len; ++i,j-=4)
       str[i] = digits[(w>>j) & 0x0f];
	return str;
}

String s = x.ToString("x")

import std.format;

s = format("%x", x);

import std.conv;

s = to!string(x, 16);

var s = x.toRadixString(16);

s = Integer.to_string(x, 16)

S = io_lib:fwrite("~.16B",[X]).

write (*,'(Z8.8)') x

import "fmt"
import "math/big"

s := fmt.Sprintf("%x", x)

Demo
Doc

import "strconv"

s := strconv.FormatInt(x, 16)

Demo
Doc

import Text.Printf (printf)

s :: String
s = printf "%x" 999

const s = x.toString(16)

String s = Integer.toHexString(x);

String s = String.format("%02x", x);

s = string.format("%x",x)

$s = dechex($x);

Demo
Doc

uses sysutils;

s := IntToHex(x);

S := Format("%x", [x]);

my $s = sprintf("%x", $i);

s = hex(x)

s = x.to_s(16)

Demo
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let s = format!("{:X}", x);

Demo
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val s = x.toString(16)

Preview