Assign to string s the hexadecimal representation (base 16) of integer x.

E.g. 999 -> "3e7"
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
char s[32];
snprintf(s, sizeof(s), "%x", i);
#include <sstream>
std::ostringstream stream;
stream << std::hex << x;
s = stream.str();
template <typename I>
std::string n2hexstr(I w, size_t hex_len = sizeof(I)<<1) {
    static const char* digits = "0123456789ABCDEF";
	std::string str(hex_len, '-');
    for (size_t i=0, j=(hex_len-1)*4 ; i<hex_len; ++i,j-=4)
       str[i] = digits[(w>>j) & 0x0f];
	return str;
String s = x.ToString("x")
import std.format;
s = format("%x", x);
import std.conv;
s = to!string(x, 16);
var s = x.toRadixString(16);
s = Integer.to_string(x, 16)
S = io_lib:fwrite("~.16B",[X]).
write (*,'(Z8.8)') x
import "fmt"
import "math/big"
s := fmt.Sprintf("%x", x)
import "strconv"
s := strconv.FormatInt(x, 16)
import Text.Printf (printf)
s :: String
s = printf "%x" 999
const s = x.toString(16)
String s = Integer.toHexString(x);
String s = String.format("%02x", x);
s = string.format("%x",x)
$s = dechex($x);
uses sysutils;
s := IntToHex(x);
S := Format("%x", [x]);
my $s = sprintf("%x", $i);
s = hex(x)
s = x.to_s(16)
let s = format!("{:X}", x);