Assign to string s the hexadecimal representation (base 16) of integer x.
E.g. 999 -> "3e7"
char s[32]; snprintf(s, sizeof(s), "%x", i);
std::ostringstream stream; stream << std::hex << x; s = stream.str();
template <typename I>
std::string n2hexstr(I w, size_t hex_len = sizeof(I)<<1) {
static const char* digits = "0123456789ABCDEF";
std::string str(hex_len, '-');
for (size_t i=0, j=(hex_len-1)*4 ; i<hex_len; ++i,j-=4)
str[i] = digits[(w>>j) & 0x0f];
return str;
}
String s = x.ToString("x")
s = format("%x", x);
s = to!string(x, 16);
var s = x.toRadixString(16);
s = Integer.to_string(x, 16)
S = io_lib:fwrite("~.16B",[X]).
write (*,'(Z8.8)') x
s := strconv.FormatInt(x, 16)
s := fmt.Sprintf("%x", x)
s :: String s = printf "%x" 999
const s = x.toString(16)
String s = "%x".formatted(x);
String s = Integer.toHexString(x);
String s = HexFormat.of().toHexDigits(x);
(setf s (format nil "~X" x))
s = string.format("%x",x)
$s = dechex($x);
S := Format("%x", [x]);
s := IntToHex(x);
my $s = sprintf("%x", $i);
s = hex(x)
s = format(x, 'x')
s = '%x' % x
s = x.to_s(16)
let s = format!("{:X}", x);
val s = x.toString(16)