Logo

Programming-Idioms

# 166 Concatenate two lists
Create the list ab containing all the elements of the list a, followed by all the elements of the list b.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations 
(def ab (concat a b))
auto ab = a;
ab.insert (ab.end (), b.begin (), b.end ());

System.Linq
var list1 = new List<int>(){1,2,3};
var list2 = new List<int>(){4,5,6};

var list3 = list1.Concat(list2);
int[] a, b;
auto ab = a ~ b;
std.range;
int[] a, b;
auto ab = chain(a, b);
var ab = a + b;
ab = a ++ b
AB = A ++ B.
real, dimension(:), allocatable :: ab

ab = [a, b]
ab := append(a, b...)
var ab []T
ab = append(append(ab, a...), b...)
ab := make([]T, len(a)+len(b))
copy(ab, a)
copy(ab[len(a):], b)
ab = a ++ b
var ab = a.concat(b);
var ab = new ArrayList<>(a);
ab.addAll(b);
import java.util.ArrayList;
import java.util.List;
List<?> ab = new ArrayList<>(a) {{ addAll(b); }};
val ab = a + b
(setf ab (append a b))
ab = {}

table.foreach(a, function(k, v) table.insert(ab, v) end)
table.foreach(b, function(k, v) table.insert(ab, v) end)
ab = {}

table.move(a, 1, #a, 1, ab)
table.move(b, 1, #b, #ab + 1, ab)
@import Foundation;
NSArray *ab=[a arrayByAddingObjectsFromArray:b];
$ab = array_merge($a, $b);
uses classes;
var
  a,b,ab: TList;

...
  ab := TList.Create;
  ab.Assign(a);
  ab.AddList(b);
...
@ab = (@a, @b)
ab = a + b
ab = a + b
let ab = [a, b].concat();
val ab = a ++ b
val ab = a ::: b
(define ab (append a b))
ab := a,b

Preview