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Idiom #166 Concatenate two lists

Create list ab containing all the elements of list a, followed by all elements of list b.

(def ab (concat a b))
auto ab = a;
ab.insert (ab.end (), b.begin (), b.end ());
var list1 = new List<int>(){1,2,3};
var list2 = new List<int>(){4,5,6};

var list3 = list1.Concat(list2);
int[] a, b;
auto ab = a ~ b;
int[] a, b;
auto ab = chain(a, b);
var a = [1,2,3];
var b = [3,2,4];
var ab = a + b;
ab = a ++ b
AB = A ++ B.
real, dimension(:), allocatable :: ab

ab = [a, b]
ab := make([]T, len(a)+len(b))
copy(ab, a)
copy(ab[len(a):], b)
var ab []T
ab = append(append(ab, a...), b...)
ab := append(a, b...)
ab = a ++ b
var ab = a.concat(b);
var ab = new ArrayList<>(a);
(setf ab (append a b))
ab = {}

table.foreach(a, function(k, v) table.insert(ab, v) end)
table.foreach(b, function(k, v) table.insert(ab, v) end)
@import Foundation;
NSArray *ab=[a arrayByAddingObjectsFromArray:b];
$ab = array_merge($a, $b);
  a,b,ab: TList;

  ab := TList.Create;
@ab = (@a, @b)
ab = a + b
ab = a + b
let ab = [a, b].concat();
val ab = a ++ b
(define ab (append a b))

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