Idiom #237 Xor integers

Assign to c the result of (a xor b)

int c = a ^ b;

(def c (bit-xor a b))

int c = a ^ b;

int c = a ^ b;

var c = a ^ b;

use Bitwise

c = a ^^^ b

C = A bxor B

c = ieor(a,b)

import "math/big"

c := new(big.Int)
c.Xor(a, b)

c := a ^ b

import Data.Bits (xor)

c = xor a b

const c = a ^ b;

int c = a ^ b;

c := a xor b;

my $c = $a ^ $b;

c = a ^ b

c = a ^ b

let c = a ^ b;

Dim c As Integer = a Xor b

Do you know the best way to do this in your language ? New implementation...

< > ⌨

Idiom created by programming-idioms.org

History

Related idioms

Issues