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Programming-Idioms

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  • Ruby

Idiom #18 Depth-first traversal of a tree

Call a function f on every node of a tree, in depth-first prefix order

A tree having 6 nodes, rooted at node 1
def dfs(f, node)
  f.(node)
  node.children.each do |child|
    dfs(f, child)
  end
end
void dfs(const auto &tree, const auto &root)
{
	f(root);

	for (auto child : tree)
		dfs(tree, child);
}

New implementation...