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Programming-Idioms

  • Erlang
  • Haskell

Idiom #18 Depth-first traversal of a tree

Call a function f on every node of a tree, in depth-first prefix order

A tree having 6 nodes, rooted at node 1
preordered (Node pivot left right) = 
   pivot : preordered left ++ preordered right
preordered Ø = []
f <$> (preordered tree)
void dfs(const auto &tree, const auto &root)
{
	f(root);

	for (auto child : tree)
		dfs(tree, child);
}

New implementation...