iterate(5, x -> x - 1)
.limit(6)
.forEach(out::println);
$values = range(0, 5);
$valuesReversed = array_reverse($values);
foreach($valuesReversed as $value)
{
printf("%s\n", $value);
}
for (int i = 5; i >= 0; --i) { std::cout << i; }
for A in reverse 0 .. 5 loop Put_Line (A'Image); end loop;
for (int i = 5; i >= 0; i--) { printf("%d\n", i); }
(doseq [n (range 5 0 -1)] (println n))
for (int i = 5; i >= 0; i--) { Console.WriteLine(i); }
for (int i = 5; i >= 0; i--) { print(i); }
do i=5,0,-1 print *,i end do
for i := 5; i >= 0; i-- { fmt.Println(i) }
foldl (\res x-> x:res) [] [0..5]
forM_ (reverse [0..5]) print
for (let i = 5; i >= 0; i--) { console.log(i) }
for (int i = 5; i != -1; out.println(i--));
iterate(5, x -> x - 1) .limit(6) .forEach(out::println);
for(int i=5 ; i>=0 ; i--) { System.out.println(i); }
(dotimes (i 6) (print (- 5 i)))
for i=5, 0, -1 do print(i) end
$values = range(0, 5); $valuesReversed = array_reverse($values); foreach($valuesReversed as $value) { printf("%s\n", $value); }
for i := 5 downto 0 do writeln(i);
print "$_\n" for reverse (0..5);
for i in range(5, -1, -1): print(i)
print(*reversed(range(6)), sep='\n')
5.downto(0){|n| puts n }
(0..=5).rev().for_each(|i| println!("{}", i));
for i in (0..=5).rev() { println!("{}", i); }
(let loop ([x 5]) (when (>= x 0) (display x) (newline) (loop (sub1 x))))
5 to: 0 by: -1 do: [:i | Transcript showln: i asString].
For i = 5 To 0 Step -1 Console.WriteLine(i) Next