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Programming-Idioms

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  • Fortran

Idiom #291 Remove sublist

Delete all the elements from index i (included) to index j (excluded) from the list items.

items = [items(:,i-1), items(j:)]

items needs to be an allocatable array. It is reallocated on assignment to a constructor containing the elements from the start of the array to i-1 and from j to the end.
items.removeRange(i, j);
New implementation...
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items = [items(:,i-1), items(j:)]
items.removeRange(i, j);
items = slices.Delete(items, i, j)
items = append(items[:i], items[j:]...)
copy(items[i:], items[j:])
for k, n := len(items)-j+i, len(items); k < n; k++ {
	items[k] = nil
}
items = items[:len(items)-j+i]
items.removeAll(items.subList(i, j));
local function erase(t,i,j)
 for i=1,j-1 do
  t[i]=nil
 end
end
erase(items,i,j)
for index := j-1 downto i do
  items.delete(index);
splice @items, $i, ($j - $i);
items[i:j] = []
del items[i:j]
s = slice(i, j)
items[s] = []
items.slice!(i...j)
items.drain(i..j)