Declare an array a of integers with six elements, where the first index is 42 and consecutive elements have the indices 43, 44, 45, 46, 47.
int a[] = new int[42 + 6]; for (int i = 42, n = 42 + 6; i < n; ++i) { }
A : array (42 .. 47) of Integer;
integer, dimension(42:47) :: a
var a: array[42..47] of integer;
use feature 'say';
use Array::Base +42; my @a = ('A'..'Z'); say $a[42]; # prints A say $a[43]; # prints B no Array::Base; # restore indexing to base 0
import array
a = array.array("i", range(42,48))
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