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Programming-Idioms

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Idiom #342 Leap year?

Determine if the current year is a leap year.

from datetime import date
y = date.today().year
b = not y % 4 and bool(y % 100 or not y % 400)
import calendar
import datetime
if calendar.isleap(datetime.date.today().year):
    print('This year is a leap year.')
final thisYear = DateTime.now().year;
final isLeap = DateTime(year, 2, 29).month == 2;
import static java.lang.Integer.parseInt;
import static java.lang.System.currentTimeMillis;
int y = parseInt("%tY".formatted(currentTimeMillis()));
boolean b = y % 4 == 0 && (y % 100 != 0 || y % 400 == 0);
import java.time.Year;
boolean b = Year.now().isLeap();
SysUtils
if IsLeapYear(SomeYear) then writeln('SomeYear is a leap year')
require 'date'

Date.leap?( Date.today.year )
let leap_year = year % 4 == 0 && (year % 100 != 0 || year % 400 == 0);
New implementation...
< > ⌨
steenslag 
y = date.today().year
b = not y % 4 and bool(y % 100 or not y % 400)
if calendar.isleap(datetime.date.today().year):
    print('This year is a leap year.')
final thisYear = DateTime.now().year;
final isLeap = DateTime(year, 2, 29).month == 2;
int y = parseInt("%tY".formatted(currentTimeMillis()));
boolean b = y % 4 == 0 && (y % 100 != 0 || y % 400 == 0);
boolean b = Year.now().isLeap();
if IsLeapYear(SomeYear) then writeln('SomeYear is a leap year')
Date.leap?( Date.today.year )
let leap_year = year % 4 == 0 && (year % 100 != 0 || year % 400 == 0);