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Programming-Idioms

  • Java
  • Ruby
  • Php

Idiom #55 Convert integer to string

Create the string representation s (in radix 10) of the integer value i.

Turning the integer 123 into the string "123" 
$s = "$i";
$s = (string)$i;
$s = "{$i}";
$s = strval($i);
String s=((Integer)i).toString();
String s = "";
while (i != 0) {
    s = i % 10 + s;
    i = i / 10;
}
String s = "%d".formatted(i);
String s = String.valueOf(i);

This is a static method.
String s = Integer.toString(i);

This is a static method, no need to create an Integer instance.
String s = "" + i;
s = i.to_s
S : String := Integer'Image (I);
New implementation...
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$s = "$i";
$s = (string)$i;
$s = "{$i}";
$s = strval($i);
String s=((Integer)i).toString();
String s = "";
while (i != 0) {
    s = i % 10 + s;
    i = i / 10;
}
String s = "%d".formatted(i);
String s = String.valueOf(i);
String s = Integer.toString(i);
String s = "" + i;
s = i.to_s
S : String := Integer'Image (I);
char s[0x1000]={};
itoa(i,s,10);
(let [s (str i)])
auto s = std::to_string(i);
string s = i.ToString()
string s = i.to!string;
var s = "$i";
s = to_string(i)
s = Integer.to_string(i)
s = "#{i}"
S = integer_to_list(I).
  write (unit=s,fmt=*) i
s := fmt.Sprintf("%d", i)
s := strconv.FormatInt(i, 10)
s := strconv.Itoa(i)
def s = "$i".toString()

let s = show i
var s = i + "";
var s = i.toString();
val s = i.toString()
(setf s (princ-to-string i))
s = tostring(i)
NSString *s=@(i).description;
Str(i,s);
var
  _s: String;
  _i: Integer;
begin
  _s := IntToStr(_i);
end.
$s = "$i";
my $s = "" . $i;
s = str(i)
let s = format!("{}", i);
let s = i.to_string();
val s = i.toString
(define s (number->string i))
s := i asString.
Dim myInt As Integer = 12345
Console.WriteLine(myInt.ToString)