Idiom #55 Convert integer to string

Create the string representation s (in radix 10) of the integer value i.

String s = "";
while (i != 0) {
    s = i % 10 + s;
    i = i / 10;
}

String s = String.valueOf(i);

String s = Integer.toString(i);

String s = "%d".formatted(i);

String s = "" + i;

String s=((Integer)i).toString();

S : String := Integer'Image (I);

#include <stdlib.h>

char s[0x1000]={};
itoa(i,s,10);

(let [s (str i)])

#include <string>

auto s = std::to_string(i);

string s = i.ToString()

import std.conv;

string s = i.to!string;

var s = "$i";

s = to_string(i)

s = "#{i}"

s = Integer.to_string(i)

S = integer_to_list(I).

  write (unit=s,fmt=*) i

import "strconv"

s := strconv.FormatInt(i, 10)

import "fmt"

s := fmt.Sprintf("%d", i)

import "strconv"

s := strconv.Itoa(i)

def s = "$i".toString()

let s = show i

var s = i + "";

var s = i.toString();

val s = i.toString()

(setf s (princ-to-string i))

s = tostring(i)

@import Foundation;

NSString *s=@(i).description;

$s = strval($i);

$s = "$i";

$s = (string)$i;

$s = "{$i}";

Str(i,s);

uses SysUtils;

var
  _s: String;
  _i: Integer;
begin
  _s := IntToStr(_i);
end.

$s = "$i";

my $s = "" . $i;

s = str(i)

s = i.to_s

let s = i.to_string();

let s = format!("{}", i);

val s = i.toString

(define s (number->string i))

s := i asString.

Dim myInt As Integer = 12345
Console.WriteLine(myInt.ToString)

Do you know the best way to do this in your language ? New implementation...

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Idiom created by programming-idioms.org

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