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Programming-Idioms

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  • Pascal

Idiom #66 Big integer exponentiation

Calculate the result z of x power n, where x is a big integer and n is a positive integer.

NCalc
  z := PowerN(x, n);

FreePascal (or Delphi) don't come with built-in support for big integers, so you need a 3rd party implementation, such as NCalc in this example.
(There are far better big integer implementations for FreePascal/Delphi than this one...)
using System.Numerics;
var z = BigInteger.Pow(x, n);
New implementation...
< > ⌨
programming-idioms.org 
  z := PowerN(x, n);
var z = BigInteger.Pow(x, n);
BigInt z = x ^^ n;
var z = pow(x, n);
z = :math.pow(x, n)
nb := big.NewInt(int64(n))
var z big.Int
z.Exp(x, nb, nil)
z = x ^ n
let z = x**n
BigInteger z = x.pow(n);
my ($x, $y) = (3 ** 200, 25);
my $z = $x ** $y;
z = x**n
z = x ** n
let z = num::pow(x, n);
z := x raisedTo: n.
z := x ** n.