Idiom #66 Big integer exponentiation

Calculate the result z of x power n, where x is a big integer and n is a positive integer.

import "dart:math";

var z = pow(x, n);

using System.Numerics;

var z = BigInteger.Pow(x, n);

import std.bigint;

BigInt z = x ^^ n;

z = :math.pow(x, n)

import "math/big"

nb := big.NewInt(int64(n))
var z big.Int
z.Exp(x, nb, nil)

z = x ^ n

let z = x**n

import java.math.BigInteger;

BigInteger z = x.pow(n);

use bigint;

my ($x, $y) = (3 ** 200, 25);
my $z = $x ** $y;

z = x**n

z = x ** n

extern crate num;

let z = num::pow(x, n);

z := x raisedTo: n.

z := x ** n.

Do you know the best way to do this in your language ? New implementation...

< > ⌨

Idiom created by programming-idioms.org

History

Related idioms

Issues