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Programming-Idioms

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  • Perl

Idiom #103 Load XML file into object

Read from the file data.xml and write its contents into the object x.
Assume the XML data is suitable for the type of x. 

use XML::LibXML qw();
my $x = XML::LibXML->load_xml(
location => 'data.xml');
using System.Xml.Linq;
XDocument x = XDocument.Load("data.xml");
New implementation...
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my $x = XML::LibXML->load_xml(
location => 'data.xml');
XDocument x = XDocument.Load("data.xml");


XmlArchive archive = new XmlArchive!(char);
archive.doc.parse(read("data.xml"));
Serializer ser = new Serializer(archive);
ser.deserialize(x);
buffer, err := os.ReadFile("data.xml")
if err != nil {
	return err
}
err = xml.Unmarshal(buffer, &x)
if err != nil {
	return err
}
def x = new XmlSlurper().parse(new File('data.xml'))
(let ((x (plump:parse #p"data.xml")))
  ...)
x = lxml.etree.parse('data.xml')
val xml = XML.loadFile("data.xml")