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Programming-Idioms

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  • Groovy

Idiom #103 Load XML file into object

Read from the file data.xml and write its contents into the object x.
Assume the XML data is suitable for the type of x. 

def x = new XmlSlurper().parse(new File('data.xml'))
using System.Xml.Linq;
XDocument x = XDocument.Load("data.xml");
New implementation...
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def x = new XmlSlurper().parse(new File('data.xml'))
XDocument x = XDocument.Load("data.xml");


XmlArchive archive = new XmlArchive!(char);
archive.doc.parse(read("data.xml"));
Serializer ser = new Serializer(archive);
ser.deserialize(x);
buffer, err := os.ReadFile("data.xml")
if err != nil {
	return err
}
err = xml.Unmarshal(buffer, &x)
if err != nil {
	return err
}
(let ((x (plump:parse #p"data.xml")))
  ...)
my $x = XML::LibXML->load_xml(
location => 'data.xml');
x = lxml.etree.parse('data.xml')
val xml = XML.loadFile("data.xml")